Sed Regular Expressions: Difference between revisions
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=External= | |||
* https://www.gnu.org/software/sed/manual/html_node/Regular-Expressions.html | |||
=Internal= | =Internal= | ||
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{ | { | ||
} | } | ||
</font> | </font> | ||
==<tt>+</tt>== | |||
<code>+</code> by itself is not a meta-character, it matches "+". | |||
The GNU version matches <code>\+</code> with "one or more characters" | |||
=Grouping= | =Grouping= |
Latest revision as of 21:46, 1 April 2024
External
Internal
Meta-Characters - Special Characters (need to be escaped in regular expressions)
/ " $ # unescaped signifies end of line ^ # unescaped signifies the beginning of a line ! [ ] : * # zero or more . # dot
Single quote is a special case, to match it use its ASCII hexadecimal value prefixed by \x as follows, instead of escaping it:
\x27
To use () for grouping, they need to be escaped:
\(...\)
More details in Grouping below.
Non-Special Characters (do not need to be escaped in regular expressions)
< > ( ) ! - { }
+
+
by itself is not a meta-character, it matches "+".
The GNU version matches \+
with "one or more characters"
Grouping
Use \( and \) for grouping. Parentheses must be escaped to be interpreted as grouping separator.
Brackets
Brackets mean "any one of"
[ab]
will match "a" or "b".
echo "blah" | sed -s 's/[ab]/x/g'
prints "xlxh".
Brackets and Negation
Match everything except the specified characters. More than one characters is matched. The behavior is different from the behavior of bash patterns on negation:
[^abc]*
Match Zero or One Character
Normally, this would be achieved with ?
placed after the character or the group of characters in questions, but this not work with standard sed
.
Examples
Match everything except space:
[^ ]*
.*
seems to work too.
Words (digits, alpha, _):
sed -e 's/[0-9a-zA-Z_]*/THIS_WAS_A_WORD/g'
Blank spaces (spaces, tabs, newlines): \s does not seem to work.
Regular Expression Syntax
TO NORMALIZE across java Regular Expression Syntax, grep Regular Expression Syntax, sed Regular Expression Syntax.