Go Once: Difference between revisions

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==<tt>Do()</tt>==
==<tt>Do()</tt>==
The only argument of <code>Do()</code> is a function value, not a function invocation. <code>Do()</code> will use the function value to invoke the function, internally. All invokers will block, except one, which executes synchronously in the same goroutine that performed the <code>Do()</code> invocation. The blocked invokers will be released after the one that does initialization finishes executing, and none of them will execute.
The only argument of <code>Do()</code> is a function value, not a function invocation. <code>Do()</code> will use the function value to invoke the function, internally. All invokers will block, except one, which executes synchronously in the same goroutine that performed the <code>Do()</code> invocation. The blocked invokers will be released after the one that does initialization finishes executing, and none of them will execute.
Note that <code>Do()</code> will execute only once, ever, not only once per unique function it is invoked with. <code>Do()</code> counts the number of times it is called, not how many times unique functions were passed to it.

Revision as of 23:16, 16 January 2024

Internal

Overview

Once is a Go synchronization construct that is used when a piece of code must be executed only once. This is a useful idiom in initialization. Note that the code is executed synchronously, when it is executed: the invocation to Once#Do() executes in the same goroutine that makes the Once#Do() invocation.

This pattern is thread-safe when the initialization is attempted by more than one goroutine.

Example

var log Log
var initLogOnce sync.Once

...
func GetLog() {
  initLogOnce.Do(func() {
     log = ... // init the log
  })
  return log // because the function passed to Do() executes synchronously, log will be initialized here.
}

Methods

Do()

The only argument of Do() is a function value, not a function invocation. Do() will use the function value to invoke the function, internally. All invokers will block, except one, which executes synchronously in the same goroutine that performed the Do() invocation. The blocked invokers will be released after the one that does initialization finishes executing, and none of them will execute.

Note that Do() will execute only once, ever, not only once per unique function it is invoked with. Do() counts the number of times it is called, not how many times unique functions were passed to it.