Go WaitGroup: Difference between revisions
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* [[Go_Package_sync#WaitGroup|The <tt>sync</tt> package]] | * [[Go_Package_sync#WaitGroup|The <tt>sync</tt> package]] | ||
* [[Go_Language_Goroutines#WaitGroup|Goroutines]] | * [[Go_Language_Goroutines#WaitGroup|Goroutines]] | ||
* [[Go Blocking the Main Thread until Ctrl-C is Entered|Blocking the Main Thread until Ctrl-C is Entered]] | |||
=Overview= | =Overview= |
Revision as of 23:22, 14 December 2023
External
Internal
Overview
A WaitGroup
is a counting semaphore that waits for a set of goroutines to finish.
The main goroutine calls Add()
to set the number of goroutines to wait for. It increments the counting semaphore. Then it should block on Wait()
, or it can do some work and then block on Wait()
until all other goroutines have finished. When each of the counted goroutines runs, they should call Done()
when finished, to decrement the counting semaphore.
import "sync"
func aFunction(wg *sync.WaitGroup, s string) {
defer wg.Done()
fmt.Println(s)
}
...
wg := sync.WaitGroup{}
wg.Add(2)
go aFunction(&wg, "A")
go aFunction(&wg, "B")
wg.Wait()
fmt.Println("main is done")
Result:
B A main is done
Note that the WaitGroup
instance must be passed to the functions executed on the counted goroutines by pointer, not value, because otherwise a copy of the sync.WaitGroup
struct will be made on the secondary goroutine's stack, as all arguments are passed by value, and the Done()
will have no effect on the original struct instance.
The same semantics, when just one single goroutine is involved, can be achieved by using an unbuffered channel and discarding the read result: