Numbers and Arithmetic in bash
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Internal
How to Tell if a Variable has an Integer Value
v=10
if expr ${v} + 1 >/dev/null 2>&1; then
#
# the value contained by v is an integer
#
else
#
# the value contained by v is NOT an integer
#
fi
More details:
Integral Number Operations
$((...))
op1=4
op2=2
echo $((op1 + op2))
echo $((op1 - op2))
echo $((op1 * op2))
echo $((op1 / op2)) # integral division
echo $((op1 % op2)) # modulo
echo $((op1 += op2))
displays:
6
2
8
2
echo $(($(date '+%s') % 2))
also works.
expr
bc
local t0="$(date -u +%s)"
local t1="$(date -u +%s)"
local delta="$(bc <<<"${t1}-${t0}")"
Floating Point Operations
Multiplication:
local operand1=10.1
local operand2=20.2
result=$(echo ${operand1} ${operand2} | awk '{printf "%5.1f\n",$1*$2}') || exit 1
result=$(echo ${operand1} ${operand2} | awk '{printf "%.1f\n",$1*$2}') || exit 1
Division:
local operand1=10.1
local operand2=20.2
result=$(echo ${operand1} ${operand2} | awk '{printf "%5.1f\n",$1/$2}') || exit 1
Increment an Integer
Decrement an Integer
Numeric Evaluation in a Condition
a=1
b=2
if [[ $((a - b)) -lt 0 ]]; then
...
fi
if [[ $(expr ${a} - ${b}) < 0 ]]; then
...
fi