Karatsuba Multiplication
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Time Complexity
In absence of Gauss optimization, the naive recursive algorithm makes 4 recursive calls (a=4), each call on half of the problem (b=2). Upon the exit from recursion, the combine phase performs additions using a number of operations proportional to the size of the current problem, so the combine phase is O(n1) (d=1). a/bd = 4/21 = 2, so we are in Case 3 of the master theorem, and the running time is upper bound by O(nlogb4)=O(n2), not better than the straightforward iterative algorithm.
TODO
- problem statement
- naïve solution
- Gauss trick
- complexity
- Karatsuba: explain the key idea – apply the master theorem to demonstrate that the complexity is still O(n2). The key insight for Karatsuba algorithm is the Gauss’ trick to reduce four sub-parts recursive multiplications to 3, and the complexity is ?
Link to Strassen.
Overview
Apply the Gauss' trick and end up with three recursive calls instead of four. This yields a O(n*logn) complexity. It if was four, the recursive complexity it would have been O(n2).
TODO