Fibonacci Numbers

From NovaOrdis Knowledge Base
Jump to navigation Jump to search

Internal

Overview

We define Fibonacci numbers by the following recurrence:

F0 = 0

F1 = 1

Fi = Fi-1 + Fi-2 for i ≥ 2.

TODO CLRS page 108.

Golden Ratio

φ=1.6180339...


Algorithms

Straightforward Recursive

A straightforward recursive algorithm looks like this:

public static long fib(long n) {
  if (n == 0) {
    return 0;
  }
  if (n == 1) {
    return 1;
  }
  return fib(n - 1) + fib(n - 2);
}

However, the running time of this method, computed with a recursion tree, is O(2n):

Fibonacci Recursion Tree.png

Running time < 20 + 21 + ... + 2n-1.

This is a bad exponential time, and attempting to use the algorithm for anything larger than 50 gets problematic. The fact that we're redundantly computing the same values again and again provides a hint that we could use a dynamic programming method:

Dynamic Programming

public static long fib_dp(int n) {
  long[] a = new long[n + 1];
  a[0] = 0;
  a[1] = 1;
  for(int i = 2; i <= n; i ++) {
    a[i] = a[i-1] + a[i-2];
  }
  return a[n];
}

Also see: Template:Algorithms